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3 years ago

I need to find the value of x!!!

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

Answer:

x = 27

Step-by-step explanation:

3x + x + 72 = 180

3x + x + 72 [-72] = 180 [-72]

4x = 27

4x [/4] = 180 / 4

x = 27

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5.708 x 10v-8 in standard form<br><br> Calculator won’t answer it..

Troyanec [42]

Hi Sebastian0113,

Your Question:

5.708 x 10^-8 in standard form

Solution:

Decimal Form:

To solve this equation just divide 5.708 by 10 8 times.

= 5.708 / 10 / 10 / 10 / 10 / 10 / 10 / 10 / 10

= 0.000000005708

5.708 x 10^-8 = 0.000000005708

Standard Form:

5.708 x 10^8

5.708 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10

= 570,800,000

Answer:

Standard Form - 570,800,000

Decimal Form - 0.0000005708

8 0

3 years ago

Read 2 more answers

What is the volume of a figure that is 5cm,5cm,8cm,8cm,8cm,1cm

Ratling [72]

Answer:

the volume is 40 cm

Step-by-step explanation:

to find the volume all you need is length times width times height and you multiply it and that is your answer

7 0

3 years ago

A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an ineq

marshall27 [118]

Start with the given expression:
$x+2x+6$ .

Simplify by grouping like terms:
$3x+6$

Isolate variable terms:
$3x$

Solve for x:
$x$
$x$

Therefor the expression holds for integers less than or equal to 14.

As a check:
$x+2x+6$
$14+2(14)+6$
$46$ TRUE

and:
$x+2x+6$
$15+2(15)+6$
$51$ FALSE

The only choice that fits is A.

8 0

3 years ago

Read 2 more answers

I would like to use Brainly for my math

zmey [24]

Thats... what people do here.

8 0

3 years ago

Refer to the following information from a frequency distribution for "heights of college women" recorded to the nearest inch:The

valkas [14]

Answer: Therefore, Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Two class midpoints are 62.5 and 65.5

So, the class interval would be

$65.5-62.5=3$

So, the limits of lower class are $x_1\ and\ x_2$

The limits of upper class are $x_2\ and\ x_3$

So, it becomes,

$\dfrac{x_1+x_2}{2}=62.5\\\\x_1+x_2=62.5\times 2=125$

and

$\dfrac{x_2+x_3}{2}=65.5\\\\x_2+x_3=65.5\times 2=131$

Since we have given that interval is 3.

So, $x_2-x_1=3\ and\ x_3-x_2=3$

So, by solving all the questions, we get that

$x_2+x_1=125\\\\x_2-x_1=3\\\\-------------------------\\\\2x_2=128\\\\x_2=64\\\\x_2-x_1=3\\\\64-x_1=3\\\\x_1=61\\\\and\\\\x_3-x_2=3\\\\x_3-64=3\\\\x_3=67$

Hence, the class limits would be

(61,64) and (64,67).

And the class limits of lowest class are 61 and 64.

Therefore, Option 'A' is correct.

4 0

3 years ago