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Reika [66]
3 years ago
10

Exacta Manufacturing purchased manufacturing supplies for $4100. The manufacturing supplies have an estimated useful life of 7 y

ears and a residual value of $300. Using the straight-line method of depreciation, calculate the following. (If necessary, round your answer to the nearest cent.) a) Depreciation expense for year 1. b) Book value at the end of year 1.
Mathematics
1 answer:
lbvjy [14]3 years ago
7 0
Answer: 

Depreciation expense year 1: $ 542.86
Book value at the end of year 1: 3,557.14


Explanation:

1) Depreciation = [purchase price - residual value] / [useful life]

2) Depreciation = [$ 4100 - $ 300] / [7 years] = $ 542.86 / year


That is the depreciation expense after year 1.

3) The book value will be the purchasing value less the depreciation accumulated, which is that of one year: $ 4100 - $ 542.86 = $ 3,557.14

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Answer:

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Step-by-step explanation:

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4 years ago
Find the exact value of sin 105º.
Jet001 [13]

Answer:

sin 105 = sin (45 + 60) = sin 45 cos 60 + cos 45 sin 60, or

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                                    = -------------

                                           2√2

Step-by-step explanation:

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3 years ago
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Find the sum of this infinite geometric series where a1=0.3 and r=0.1
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Answer:

1/3

Step-by-step explanation:

The formula for computing the sum of an infinite geometric series is

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So let's plug in:

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3 years ago
Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p
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Answer:

A)

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>B)</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em> Rejected H₀</em>

<em>There is a significant difference in drug resistance between the two states.</em>

C)

P - value = 0.0066

<em>P - value = 0.0066 < 0.02</em>

<em>D) </em>

<em>1) Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first sample size n₁ = 174</em>

Suppose that, of 174 cases tested in a certain state, 11 were found to be drug-resistant.

<em>First sample proportion </em>

                    p_{1} = \frac{x_{1} }{n_{1} } = \frac{11}{174} = 0.0632

<em>Given second sample size n₂ = 375</em>

Given data  Suppose also that, of 375 cases tested in another state, 7 were found to be drug-resistant

<em>Second sample proportion</em>

<em>                  </em>p_{2} = \frac{x_{2} }{n_{2} } = \frac{7}{375} = 0.0186<em></em>

<u><em>Step(ii):-</em></u>

<u><em>Null hypothesis:H₀:-</em></u><em> There is no significant difference between in drug resistance between the two states</em>

<u><em>Alternative Hypothesis :H₁:</em></u>

<em>There is  significant difference between in drug resistance between the two states</em>

<em>Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>        Where </em>

<em>         </em>P = \frac{n_{1}p_{1} +n_{2} p_{2}  }{n_{1} +n_{2} }<em></em>

<em>        </em>P = \frac{174 (0.0632) + 375 (0.0186) }{174+375 } =  \frac{17.9718}{549} = 0.0327<em></em>

<em>       Q = 1 - P = 1 - 0.0327 = 0.9673</em>

<u><em>Step(iii):-</em></u>

<em></em>

<em>  Test statistic</em>

<em>           </em>Z = \frac{p_{1}-p_{2}  }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }<em></em>

<em>          </em>Z = \frac{0.0632-0.0186  }{\sqrt{0.0327 X 0.9673(\frac{1}{174 }+\frac{1}{375 } ) } }<em></em>

<em>       Z  =   2.7261</em>

<em>   </em>

<em>Level of significance = 0.02 or 0.98</em>

<em>The z-value = 2.054</em>

<em>The calculated value Z =  2.7261 > 2.054 at 0.02 level of significance</em>

<em>    Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

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<em>P( Z > 2.7261) = 1 - P( Z < 2.726)</em>

<em>                         = 1 - ( 0.5 + A (2.72))</em>

<em>                         = 0.5 - 0.4967</em>

<em>                          = 0.0033</em>

we will use two tailed test

<em>2 P( Z > 2.7261)  = 2 × 0.0033</em>

<em>                            = 0.0066</em>

<em>P - value = 0.0066 < 0.02</em>

<em>  Reject H₀   </em>

<em>There is a significant difference in drug resistance between the two states.</em>

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Answer:

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