Answer:
20.6
Step-by-step explanation:
Given data
J(-1, 5)
K(4, 5), and
L(4, -2)
Required
The perimeter of the traingle
Let us find the distance between the vertices
J(-1, 5) amd
K(4, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4+1)²+(5-5)²)
d=√5²
d= √25
d= 5
Let us find the distance between the vertices
K(4, 5), and
L(4, -2)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4-4)²+(-2-5)²)
d=√-7²
d= √49
d= 7
Let us find the distance between the vertices
L(4, -2) and
J(-1, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-1-4)²+(5+2)²)
d=√-5²+7²
d= √25+49
d= √74
d=8.6
Hence the total length of the triangle is
=5+7+8.6
=20.6
Answer:
- Area of the circle is 56.25π square feet.
Step-by-step explanation:
<u>Given that</u>:
- The circumference of a circle is 15π ft.
<u>To Find</u>:
- What is the area, in square feet?
<u>We know that</u>:
- Circumference of a circle = 2πR
- Area of a circle = πR²
Where,
<u>Finding the radius of the circle</u>:
Circumference of a circle = 15π
⟶ 2πR = 15π
⟶ 2πR = 2π × 7.5
Cancelling 2π.
⟶ R = 7.5
∴ Radius of the circle = 7.5 ft.
<u>Finding the area of the circle</u>:
⟶ Area = πR²
⟶ Area = π(7.5)²
⟶ Area = π × 7.5 × 7.5
⟶ Area = π × 56.25
⟶ Area = 56.25π
∴ Area of the circle = 56.25π ft.²
Answer:
Yermin
Step-by-step explanation:
The square route of 0.5 is around 0.7.
(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°: base=(180-50)/2=65°
base is 50°: vertex= 180-2*50=80°
vertex 50 base 65; vertex 80, base 50
(2)base=180-130=50°
vertex=180-2*50=80°
base 50 vertex 80