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bixtya [17]
3 years ago
12

In a study of 250 adults, the mean heart rate was 70 beats per minute. Assume the population of heart rates is known to be appro

ximately normal with a standard deviation of 12 beats per minute. What is the 99% confidence interval for the mean beats per minute
Mathematics
1 answer:
klasskru [66]3 years ago
4 0
This is a good question!

The steps are like follows:

Form the confidence level (99%), we calculate the "alpha" value
alpha=1-(99/100)=0.01

Now, calculate the critical probability (p-start)
p*=1-(alpha/2)=1-(0.01/2)=0.995

z-score could be calculated from p*,,,
z-score=<span>2.57583
(http://www.socscistatistics.com/tests/ztest/zscorecalculator.aspx)

Now, calculate the Margin of Error:
</span>standard<span> deviation = s
number of adults = n
</span><span>
ME=(z*s)/(sqrt n)=(</span><span>2.57583*12)/(sqrt 250) = 1.955

The confidence interval = mean +or- ME
                                      = 70+1.955</span>  or  70-1.955


So that we can conclude that <span>the 99% confidence interval for the mean beats per minute is 68.045 and 71.955

</span>

I hope you got the idea!

If you still need help, just let me know!





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Use proportion to find the answer.
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<u>Answer</u>

\boxed {64}


<u>Detailed Explanation </u>

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3*x=3x

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