All categories

3 years ago

2X- 10 =30 solve for X

Mathematics

2 answers:

melamori03 [73]3 years ago

8 0

<h2>Answer:</h2><h3>X = 20</h3><h2>Step-by-step explanation:</h2>

First, add 10 to both sides.

2X - 10 + 10 = 30 + 10

2X = 40

Finally, we have to divide both sides by 2!

2X / 2 = 40 / 2

X = 20

Kazeer [188]3 years ago

5 0

2x - 10 = 30
2x = 40
x = 20

You might be interested in

Any1 know the answers?

Keith_Richards [23]

One apple 10 fingers six flowers

4 0

2 years ago

Read 2 more answers

Given A = {a, e, i, o, u} and B = {a, l, g, e, b, r}, find A ∪ B.

harkovskaia [24]

Ahh..this is sets topics - A U B = all the elements found in A and B. But do note, do not repeat the elements if it is the same. And if the question were to ask : n(AUB) = total number of elements found in A and B.

3 0

3 years ago

Read 2 more answers

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

<em><u>Substitute eqn 2 in eqn 1</u></em>

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

<em><u>Solve by quadratic equation</u></em>

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

2 years ago

What is the circle's circumference? The diameter of a circle is 6 millimetres.

dolphi86 [110]

Answer:

C = 6pi or approximately 18.84 mm

Step-by-step explanation:

The circumference of a circle is

C = pi *d

C = pi *6

We can approximate pi by 3.14

C = 3.14*6

C =18.84

6 0

3 years ago

A deck builder uses 11 bags of concrete mix for every 5 deck footings. If the builder needs to build 12 deck footings, how many

juin [17]

I think it is 220 bags but i am stuipd

5 0

2 years ago