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3 years ago

2X- 10 =30 solve for X

Mathematics

2 answers:

melamori03 [73]3 years ago

8 0

<h2>Answer:</h2><h3>X = 20</h3><h2>Step-by-step explanation:</h2>

First, add 10 to both sides.

2X - 10 + 10 = 30 + 10

2X = 40

Finally, we have to divide both sides by 2!

2X / 2 = 40 / 2

X = 20

Kazeer [188]3 years ago

5 0

2x - 10 = 30
2x = 40
x = 20

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Alex17521 [72]

Answer:

$4 = (x + 7 {)}^{2} + (y - 3 {)}^{2}$

Step-by-step explanation:

equation of a circle

${r}^{2} = (x - {h} )^{2} + (y - {k)}^{2}$

we know the center is (-7, 3)

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3 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

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