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Aleksandr-060686 [28]

3 years ago

12

Circle O is shown. Line segments B D and A C intersect at point O. The length of B O is 5. Angle C O D is StartFraction 4 pi Ove

r 9 EndFraction. Sectors A O B and D O C are shaded.
Which statement is true regarding the two shaded sectors of circle O? Explain.

1 answer:

Lapatulllka [165]3 years ago

4 0

Answer:

The answer is C

Step-by-step explanation:

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A standard interior staircase has steps each with a rise (height) of 21 cm and a run (horizontal depth) of 24 cm. Research sugge

Alisiya [41]

Answer:

The staircase would extends 1.20 m if the changes were made.

Step-by-step explanation:

Acording tho the statement the total heigth is 5.04 m, that is 504 cm, each steps rises 21 cm. with this information we can calculte how many steps are in the whole staircase:

$Number steps= \frac{Total heigth}{each step} \\Number steps= \frac{504}{21} = 24 steps$

To calculate how much the staircase will extend, whe have to multiply the horizontal depth times the number of steps.

using the run of 24 cm that gives us a lengt of 576 cm and if the changes were made the new length will be 696 cm.

So the staircase would extend an amount of (696 - 576), that is 120 cm, or 1.20 m, if the changes were made.

6 0

3 years ago

2(g+5)=-7-4g+g include instructions plz!

Elza [17]

First distribute the 2, then add 7 to that side, so you have 2g+17=-4g+g , subtract 2g and it should be easy to find from there lol

4 0

3 years ago

The area of a rectangle is 54 ft?, and the length of the rectangle is 3 ft more than twice the width. Find the dimensions of the

nikklg [1K]

Answer:

prim

Step-by-step explanation:

3 0

3 years ago

You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)

Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, $v_1$ = = 20 m./s

Velocity of the truck 2, $v_2$ = 35 m./s

1. Kinetic energy of the truck 1: $\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules$

Kinetic energy of the truck 2: $\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules$

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = $mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules$

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0

3 years ago

Solve the following integral.<br><br> <img src="https://tex.z-dn.net/?f=%5Cint4x%5Ccos%282-3x%29dx" id="TexFormula1" title="\int

bagirrra123 [75]

Hi there!

$\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}$

To find the indefinite integral, we must integrate by parts.

Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":

u = 4x

du = 4

dv = cos(2 - 3x)

v = 1/3sin(2 - 3x)

Write into the format:

∫udv = uv - ∫vdu

Thus, utilize the solved for expressions above:

4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx

Simplify:

-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx

Integrate the integral:

∫4/3(sin(2 - 3x)dx

u = 2 - 3x

du = -3dx ⇒ -1/3du = dx

-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C

Combine:

$-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C$

7 0

2 years ago

Read 2 more answers