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3 years ago

Neil Armstrong weighed more on Earth than he did on the moon because the Earth has a greater

2 answers:

8 0

Neil Armstrong weighed more on Earth than he did on the moon because the Earth has a greater Gravitational Force.

Naily [24]3 years ago

7 0

Because of gravitational force. so the answer will be B)

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If inflation from last year to this year was 2% and a pair of designer jeans sold for $75 last year, what would you expect to pa

tamaranim1 [39]

Answer:

$76.5

Step-by-step explanation:

We have been given that inflation from last year to this year was 2% and a pair of designer jeans sold for $75 last year. We are asked to find the price of pair of designer jeans this year.

An inflation of 2% will increase the price of pair of jeans by 2%, so price of pair of jeans this year would be $75 plus 2% of $75.

$\text{Price of pair of jeans this year}=\$75+\$75\times\frac{2}{100}$

$\text{Price of pair of jeans this year}=\$75+\$75\times0.02$

$\text{Price of pair of jeans this year}=\$75+\$1.5$

$\text{Price of pair of jeans this year}=\$76.5$

Therefore, the price of pair of jeans would be $76.5 this year.

7 0

2 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

2 years ago

Verify this identity: secx-cosx = 1-cos^2x/cosx

Sauron [17]

Step-by-step explanation:

sec x − cos x

Secant is the inverse of cosine:

(1 / cos x) − cos x

Find the common denominator:

(1 / cos x) − (cos² x / cos x)

Subtract:

(1 − cos² x) / cos x

5 0

2 years ago

(x²+4x+4)/(x+2) algebraic expressions class 8 no spamms

maks197457 [2]

Answer:

x+2

Step-by-step explanation:

$\frac{x ^{2} + 4x + 4 }{x + 2} \\ \frac{(x) ^{2} + 2 \times x \times 2 + (2) ^{2} }{x + 2} \\ \ \frac{(x + 2) ^{2} }{x + 2} \\ \frac{(x + 2)(x + 2)}{x + 2} \\ x + 2$

5 0

2 years ago

Help please:) please describe how you got the answer and will give big thanks!

ozzi

You can cross out c and d I think its B but im not positive

7 0

3 years ago