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Alexxandr [17]
2 years ago
8

George and Francis are studying for a math test. They are each trying to find the product below.

Mathematics
2 answers:
torisob [31]2 years ago
7 0

Answer:

They are correct

Step-by-step explanation:

5 is equal to \frac{5}{1}

\frac{5}{1} × \frac{5}{3} = \frac{25}{3}

\frac{25}{3} is about equal to 8.33

8.33 is greater than 5

Vedmedyk [2.9K]2 years ago
6 0

<u>Answer: </u>

The product is greater than 1.

<u>Solution: </u>

They are trying to find the product of 5 times of \frac{5}{3}

So the product will be 5 times of \left(\frac{5}{3}\right)=\left(5 \times\left(\frac{5}{3}\right)\right)

\Rightarrow\frac{5 \times 5}{3}\\=\frac{25}{3}=\frac{8 \times 3+1}{3}\\\Rightarrow8\left(\frac{1}{3}\right)

8\left(\frac{1}{3}\right) > 1

So, we can see that the product is greater than 1.

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Step2247 [10]

Answer:

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Step-by-step explanation:

Pretty sure it's correct

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Richie and Phoebe are saving money to buy a new tv. They need at least $510 to purchase the new TV. Phoebe weeds yards and Richi
den301095 [7]

Answer:

  • 12x +9y ≥ 510
  • y ≤ 2x
  • y ≥ 25

Step-by-step explanation:

Phoebe earns 12x for her yard weeding, and Richie earns 9y for his dog walking. They want the sum of these earnings to be at least 510, so the first constraint inequality is ...

  12x +9y ≥ 510

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Richie plans to walk no more than 2x dogs, since y is the number of dogs he walks, the second constraint is ...

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6 0
3 years ago
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We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu
Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

Total                  2298                     170                  2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0
3 years ago
1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

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= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
8 0
2 years ago
Need help rn plz thanks
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Answer:

Figure RST is congruent is R´S´T´

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Given that R´S´T is a reflection of RST, we know that is a rigid transformation, so it is congruent (the same size & shape).

4 0
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