Question

Factor 6m^2+25mn+11n^2 and if you can please tell me a step-by-step explanation, please! Thanks :)

Answer 1

For this case, we have to factor the following expression:

$6m ^ 2 + 25mn + 11n ^ 2$

The term that is in the middle must be rewritten as a sum of two terms whose product is:

$6 * 11 = 66$

and whose sum is 25.

Those numbers are 22 and 3.

$22 * 3 = 66\\22 + 3 = 25$

Rewriting the term of the medium we have:

$6m ^ 2 + 3mn + 22mn + 11n ^ 2$

We factor the maximum common denominator of each group:

$3m (2m + n) + 11n (2m + n)$

We factor the polynomial by factoring the maximum common denominator, $(2m + n)$:

$(2m + n) (3m + 11n)$

Answer:

$(2m + n) (3m + 11n)$

Answer 2

idk ......sorry‍♀️‍♀️‍♀️