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i entered sin(48) into my calculator and got the answer above
Since we have a cubic root, we're interested in factoring cubes inside the root, so that we can take them out. If we factor 648, we have

So, we have
![3x\sqrt[3]{648 x^4 y^8} = \sqrt[3]{3\times 6^3\cdot x^3\cdot x \cdot y^6\cdot y^2}=3x\cdot 6\cdot x\cdot y^2\sqrt[3]{3\cdot x\cdot y^2}](https://tex.z-dn.net/?f=3x%5Csqrt%5B3%5D%7B648%20x%5E4%20y%5E8%7D%20%3D%20%5Csqrt%5B3%5D%7B3%5Ctimes%206%5E3%5Ccdot%20x%5E3%5Ccdot%20x%20%5Ccdot%20y%5E6%5Ccdot%20y%5E2%7D%3D3x%5Ccdot%206%5Ccdot%20x%5Ccdot%20y%5E2%5Csqrt%5B3%5D%7B3%5Ccdot%20x%5Ccdot%20y%5E2%7D)
And the result simplifies to
![18x^2y^2\sqrt[3]{3xy^2}](https://tex.z-dn.net/?f=18x%5E2y%5E2%5Csqrt%5B3%5D%7B3xy%5E2%7D)
We hates fractions
times everybody by 6x
6=x²-5x
minus 6 both sides
0=x²-5x-6
factor
what 2 numbers multiply toget -6 and add to get -5
-6 and 1
0=(x-6)(x+1)
set to zero
x-6=0
x=6
x+1=0
x=-1
x=6 or -1
Answer:
<h3>There equal (-3)=3</h3>
Step-by-step explanation:
<h3> 3 is the same distance from 0 than -3</h3>