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Rus_ich [418]
3 years ago
14

You have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always

have your reindeer fly in a single-file line. How many different ways can you arrange your reindeer?
Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

360

Step-by-step explanation:

velikii [3]3 years ago
5 0

Answer:

120 ways.

Step-by-step explanation:

We have been given that you have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always have your reindeer fly in a single-file line.

We will use permutation formula to solve our given problem as:

_{r}^{n}\textrm{C}=\frac{n!}{(n-r)!}

_{3}^{6}\textrm{C}=\frac{6!}{(6-3)!}

_{3}^{6}\textrm{C}=\frac{6\cdot 5\cdot 4\cdot 3!}{3!}

_{3}^{6}\textrm{C}=6\cdot 5\cdot 4

_{3}^{6}\textrm{C}=120

Therefore, you can arrange your reindeer in 120 different ways.

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ANTONII [103]

Answer:

She forgot to flip the inequality sign when dividing both sides by -4

8 0
3 years ago
Read 2 more answers
The cost for 16 ounces of cheese is $3.20. What is the cost for 20 ounces of cheese?
9966 [12]

Answer:

It costs $4 dollars for 20 ounces of cheese.

Step-by-step explanation:

First we find out how many dollars for 1 ounce of cheese.

3.20 ÷ 16 = 0.2

Next we multiply 0.2 by 20.

20 * 0.2 = 4

So, the answer is 4 dollars.

Hope this helps! :)

8 0
3 years ago
A. 46 <br> B. 72<br> C.45<br> D.36
ASHA 777 [7]

Answer: C 45

Step-by-step explanation:

7 0
3 years ago
3. A basket of beads contains 8 red beads, 6 yellow beads, and 6 green beads. A
Ipatiy [6.2K]

Answer:

A) 45

Step-by-step explanation:

P(green) = 6/20

6/20 = x/150

20x = 900

x = 45

7 0
3 years ago
Find the surface area of the surface given by the portion of the paraboloid z=3x2+3y2 that lies inside the cylinder x2+y2=4. (hi
natta225 [31]
Parameterize the part of the paraboloid within the cylinder - I'll call it S - by

\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\left\langle u\cos v,u\sin v,3u^2\right\rangle

with 0\le u\le2 and 0\le v\le2\pi. The region's area is given by the surface integral

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=2}\int_{v=0}^{v=2\pi}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du\,\mathrm dv
=\displaystyle2\pi\int_{u=0}^{u=2}u\sqrt{1+36u^2}\,\mathrm du

Take w=1+36u^2 so that \mathrm dw=72u\,\mathrm du, and the integral becomes

=\displaystyle\frac{2\pi}{72}\int_{w=1}^{w=145}\sqrt w\,\mathrm dw
=\displaystyle\frac\pi{36}\frac23w^{3/2}\bigg|_{w=1}^{w=145}
=\dfrac\pi{54}(145^{3/2}-1)\approx101.522
7 0
3 years ago
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