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Rus_ich [418]
3 years ago
14

You have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always

have your reindeer fly in a single-file line. How many different ways can you arrange your reindeer?
Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

360

Step-by-step explanation:

velikii [3]3 years ago
5 0

Answer:

120 ways.

Step-by-step explanation:

We have been given that you have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always have your reindeer fly in a single-file line.

We will use permutation formula to solve our given problem as:

_{r}^{n}\textrm{C}=\frac{n!}{(n-r)!}

_{3}^{6}\textrm{C}=\frac{6!}{(6-3)!}

_{3}^{6}\textrm{C}=\frac{6\cdot 5\cdot 4\cdot 3!}{3!}

_{3}^{6}\textrm{C}=6\cdot 5\cdot 4

_{3}^{6}\textrm{C}=120

Therefore, you can arrange your reindeer in 120 different ways.

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Answer: 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

Step-by-step explanation:

GCF = Greatest common factor.

For example: 6 is the GCF of 12 and 18.

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It can be written as

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Taking out common factor  5y , we get

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Hence, 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

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