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Rus_ich [418]
3 years ago
14

You have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always

have your reindeer fly in a single-file line. How many different ways can you arrange your reindeer?
Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

360

Step-by-step explanation:

velikii [3]3 years ago
5 0

Answer:

120 ways.

Step-by-step explanation:

We have been given that you have 6 reindeer, Prancer, Rudy, Balthazar, Quentin, Jebediah, and Lancer, and you want to have 3 fly your sleigh. You always have your reindeer fly in a single-file line.

We will use permutation formula to solve our given problem as:

_{r}^{n}\textrm{C}=\frac{n!}{(n-r)!}

_{3}^{6}\textrm{C}=\frac{6!}{(6-3)!}

_{3}^{6}\textrm{C}=\frac{6\cdot 5\cdot 4\cdot 3!}{3!}

_{3}^{6}\textrm{C}=6\cdot 5\cdot 4

_{3}^{6}\textrm{C}=120

Therefore, you can arrange your reindeer in 120 different ways.

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The one that doesn't have an "x" repeated, that is an X-REPEAT
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let's see

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6 0
3 years ago
Read 2 more answers
Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the
UNO [17]

Answer:

The price of the computer is $1,152

Step-by-step explanation:

Let the price of the computer be $x

The first boy boy had 7/8 of this amount, the amount he has is thus 7/8 × $x = 7x/8

The second boy had 5/6 of what the first boy had. The amount of money he has is thus 5/6 × 7x/8 = 35x/48

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Mathematically, this can be represented as;

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77x = 48(x + 696)

77x = 48x + 33408

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x = 33,408/29

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3 years ago
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If you want to confirm this, dividing 3/2 equals 1.5, ergo 1.5 > 1.

In essence, improper fractions will always represent a number greater than one contrasted to proper fractions because if you put it on a perspective (let's say you have 13 pie slices but you only needed 12, that means there is a pie slice that's extra that makes it greater than the original pie slices).

Hope that helps :)

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