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lapo4ka [179]
3 years ago
7

what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6

Mathematics
2 answers:
BabaBlast [244]3 years ago
8 0
Y=kx+b
line is perpendicular y=1/3x+6⇒ k=-\frac{1}{ \frac{1}{3} }=-3

 so line y=-3x+a
 this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture<span> to test solutions <span>in the application</span></span>


m_a_m_a [10]3 years ago
4 0
D: 1/3x-y+6, A(-9, 12)
md=-b/a=1/1/3=3, md=slope d

d`: y-yA=md(x-xA)
     y-12=3(x+9)
     y-12=3x+27
=> d`: 3x-y+15=0
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mamaluj [8]

Answer/Step-by-step explanation:

Volume of a cylinder is given as V = πr²h

Where,

radius (r) = 6 cm

height (h) = 8 cm

Plug in the values

V = π*6²*8

V = π*36*8

V = π*288

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3 0
3 years ago
Q#7: Solve for the variable: 3(x+2) - 9 = 15 - 4(5x - 2) Make sure you round you answer to the nearest whole number.
masya89 [10]

    - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - -  -

\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

3(x+2)-9=15-4(5x-2)

\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

  First use the distributive property of both sides:-

3(x+2)-9=15-4(5x-2)

3x+6-9=15-20x+8

Now add 20x on both sides:-

23x+6-9=15+8

On simplification,

23x-3=23

Add 3 to both sides:-

23x=26

Divide by 23 on both sides:-

x=26/23

<h3>Good luck.</h3>

     

        - - - - -- - - - - - - - - - - -  - - - - - -- - - - - - - - - - - - - - - - - - - - - - - - - - - - -

3 0
1 year ago
What’s the answer to this?
babymother [125]

Answer:

○ \displaystyle x > -3 \\ 5y ≥ -4x - 10

Step-by-step explanation:

This system of inequalities has a shared portion at the origin, so we can easily jump to using the zero-interval test [test point (0, 0)] to verify the inequalities as false or true:

\displaystyle 5[0] ≥ -4[0] - 10 → 0 ≥ -10☑

\displaystyle 0 > -3☑

Plus, the top inequality has a <em>dashed </em><em>line</em><em> </em>["<" or ">"], and the bottom inequality has a solid line, so this must have an equivalence line underneath each inequality symbol ["≤" or "≥"].

** Hold on though! Although it looks obvious about what the second inequality is, we need to double-check and make sure anyway, just to be on the safe side ☺:

\displaystyle \frac{5y}{5} ≥ \frac{-4x - 10}{5} → y ≥ -\frac{4}{5}x - 2

From the y-intercept of \displaystyle [0, -2],we do \displaystyle \frac{rise}{run}by either moving four blocks <em>north</em><em> </em>over five blocks <em>west</em><em> </em>or four blocks <em>south</em><em> </em>over five blocks <em>east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. This IS what our solid graph looks like, so we are correct!

So, from all what was explained, you have your answer.

I am joyous to assist you anytime.

8 0
2 years ago
How do you solve 4b^2+8b+-12=0. Also find the parabole.?
Likurg_2 [28]
First you divide everything by 4 which will become b^2+2b-3=0
Then you can factor this which is
(b-1)(b+3)=0
B=1
B=-3 ... I think that's how you do it
4 0
3 years ago
I need help with this question
Rudiy27
Since the angle is positive, you can find any coterminal angle by applying:


Angle + x = 2π ==> 7π/6 + x = 2π ==> x = 2π - 7π/6

x= 12π/6 -7π/6 = 5π/6

So the angle 5π/6 is the coterminal of 7π/6
8 0
3 years ago
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