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3 years ago

what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6

Mathematics

2 answers:

BabaBlast [244]3 years ago

8 0

Y=kx+b
line is perpendicular y=1/3x+6⇒ k=- $\frac{1}{ \frac{1}{3} }$ =-3

so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture to test solutions in the application

m_a_m_a [10]3 years ago

4 0

D: 1/3x-y+6, A(-9, 12)
md=-b/a=1/1/3=3, md=slope d

d`: y-yA=md(x-xA)
y-12=3(x+9)
y-12=3x+27
=> d`: 3x-y+15=0

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Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

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Option B:

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To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

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So, option B is incorrect.

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So, option C is correct.

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