Question

(5372 + 100y^2) + 5(10y^2 – 110) Add the two polynomials and write in the form ay^2 + b, where a and b are constants, What is the value of a + b?

Answer 1

Answer:

The value of a is 150 and b is 4822.

Explanation:

First, you have to expand to remove brackets :

$(5372 + 100 {y}^{2} ) + 5(10 {y}^{2} - 110)$

$= 5372 + 100 {y}^{2} + 50 {y}^{2} - 550$

Next, you have to simplify :

$100 {y}^{2} + 50 {y}^{2} + 5372 - 550$

$= 150 {y}^{2} + 4822$

Next, you have to compare it :

$a {y}^{2} + b = 150 {y}^{2} + 4822$

$a = 150$

$b = 4822$