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kondaur [170]
4 years ago
14

Largest of five (5 points). Write an algorithm that read 5 distinct integers and displays the largest value. Assume the input va

lues are distinct integers. % java LargestOfFive 17 23 5 1 6 23 % java LargestOfFive 8 3 -8 4 1 8
Computers and Technology
1 answer:
mrs_skeptik [129]4 years ago
6 0

Answer:

import java.io.*;

public class Larger {

  public static void main(String[] args) throws IOException{

       BufferedReader br=new BufferedReader(new InputStreamReader(System.in));// reading input from buffered reader

        int a,max=-99999,i;

        for(i=1;i<=5;i++)

        {

            a=Integer.parseInt(br.readLine());//converting string input string to int

            if(a >max)

               max=a;

         

        }

       System.out.println("Maximum value : "+max);

  }

Explanation:

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4 0
3 years ago
How many times is the body of the loop executed?
Flura [38]

Answer:

The loop will run 5 times.

3 0
2 years ago
Finish and test the following two functions append and merge in the skeleton file:
avanturin [10]

Answer:

Explanation:

#include <iostream>

using namespace std;

int* append(int*,int,int*,int);

int* merge(int*,int,int*,int);

void print(int*,int);

int main()

{ int a[] = {11,33,55,77,99};

int b[] = {22,44,66,88};

print(a,5);

print(b,4);

int* c = append(a,5,b,4); // c points to the appended array=

print(c,9);

int* d = merge(a,5,b,4);

print(d,9);

}

void print(int* a, int n)

{ cout << "{" << a[0];

for (int i=1; i<n; i++)

cout << "," << a[i];

cout << "}\n";

}

int* append(int* a, int m, int* b, int n)

{

int * p= (int *)malloc(sizeof(int)*(m+n));

int i,index=0;

for(i=0;i<m;i++)

p[index++]=a[i];

for(i=0;i<n;i++)

p[index++]=b[i];

return p;

}

int* merge(int* a, int m, int* b, int n)

{

int i, j, k;

j = k = 0;

int *mergeRes = (int *)malloc(sizeof(int)*(m+n));

for (i = 0; i < m + n;) {

if (j < m && k < n) {

if (a[j] < b[k]) {

mergeRes[i] = a[j];

j++;

}

else {

mergeRes[i] = b[k];

k++;

}

i++;

}

// copying remaining elements from the b

else if (j == m) {

for (; i < m + n;) {

mergeRes[i] = b[k];

k++;

i++;

}

}

// copying remaining elements from the a

else {

for (; i < m + n;) {

mergeRes[i] = a[j];

j++;

i++;

}

}

}

return mergeRes;

}

4 0
4 years ago
Four ways to improve the performance of a hard disk include.
erik [133]

Answer:

Defragmenting, and optimizing, also on Windows to not use Paging unless you have an SSD. And to install a lightweight OS like Windows 11 super-lite, Linux etc.

7 0
2 years ago
What technique is used when setup times at a workstation are sequence dependent?
grigory [225]

Answer:

johnsons rule minimizes total idle time for both machines or work centers. What technique is used when setup times at a workstation are sequence dependent? determine the total time of each job sequence permutation considering the setup time and choose the best (lowest) time.

Explanation:

please mark me as brainliest thank you

3 0
3 years ago
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