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IrinaVladis [17]
3 years ago
9

the default name for the small icon that represents a web site or page, and is displayed in the browsers, typically at the begin

ning of the url address field, is:
Computers and Technology
1 answer:
Alona [7]3 years ago
8 0

That's a favicon. A web-browser will normally look for a file called favicon.ico on the web-server, but with the following metatag, you can specify what file to look for:

<link rel="shortcut icon" href="/favicon.ico" type="image/x-icon" />

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beks73 [17]
The answer is D Compress

I hope this helps
6 0
3 years ago
Pictures that you can click on to tell your computer what to do.
Tom [10]
What do you mean ? I’m confused..
6 0
3 years ago
Read 2 more answers
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
Given the String variables name1 and name2, write a fragment of code that assigns the larger of the two to the variable first (a
Neporo4naja [7]

Answer:

if ( name1 > name2) {

    first = name1;

} else {

    first = name2;

}

Explanation:

First you need take a decision for that reason you need and if - else structure to decide if asign the variable name1 or the variable name2 to the result. Later you can use an > or < to compare two strings because it use the ASCII code to compare wich one is larger than another.

if ( name1 > name2) {

    first = name1;

} else {

    first = name2;

}

6 0
3 years ago
Define the Artist class with a constructor to initialize an artist's information and a print_info() method. The constructor shou
nika2105 [10]

Answer:

class Artist():

   def __init__(self, artist_name=None, artist_birth_year=0, artist_death_year=0):

       self.artist_name = artist_name

       self.artist_birth_year = artist_birth_year

       self.artist_death_year = artist_death_year

   def display_artist(self):

       if self.artist_death_year == -1:

           print('{}, born {}'.format(self.artist_name, self.artist_birth_year))

       else:

           print('{} ({}-{})'.format(self.artist_name, self.artist_birth_year, self.artist_death_year))

class Artwork():

   def __init__(self, artwork_title=None, artwork_year_created=0, artist=Artist()):

       self.artwork_title = artwork_title

       self.artwork_year_created = artwork_year_created

       self.artist = artist

   def display_artist(self):

       print('artwork_title: {}'.format(self.artwork_title))

       print('Artist: ', end='')

       self.artist.display_artist()

def main():

   user_artist_name = input('Enter the name of artist: ')

   user_birth_year = int(input('Enter birth year: '))

   user_death_year = int(input('Enter death year: '))

   user_title = input('Enter master piece title: ')

   user_year_created = int(input('Enter year created: '))

   user_artist = Artist(user_artist_name, user_birth_year, user_death_year)

   new_artwork = Artwork(user_title, user_year_created, user_artist)

   new_artwork.display_artist()

if __name__ == "__main__":

   main()

Explanation:  

  • Inside the constructor of Artist class, initialize the essential properties.
  • Create the display_artist function that checks whether artist_death_year is equal to -1 and then displays an appropriate message according to the condition.
  • Apply the similar steps as above for the Artwork class.
  • Inside the main method, get the information from user and finally call the display_artist function to print the results on screen.
8 0
3 years ago
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