Answer:
The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30. Otherwise, the mean and the standard deviations holds, but the distribution will not be approximately normal.
Standard deviation 4 minutes.
This means that 
A sample of 25 wait times is randomly selected.
This means that 
What is the standard deviation of the sampling distribution of the sample wait times?

The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.
C because y=mx+b and the constant is the slope which is m. The equation is y =38x+100
What is your question
asking if the results of increasing and then decreasing will be the same???
because if its that then no
A^2+b^2=c^2 (Pythagoran theorem)
-> 30^2 + length^2 = 78^2
-> length = √6084-900 = <span>√5184 = 72 ft
=> area = length x width = 72 x 30 = 2160 ft^2</span>