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iris [78.8K]
3 years ago
6

How many vertices does a sphere have?

Mathematics
1 answer:
Vinvika [58]3 years ago
5 0
Hello, a sphere has zero vertices.
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What is six thousandths as a number?
Cerrena [4.2K]

Answer:

6000

Step-by-step explanation:

6 six

60 sixty

600 six hundred

6000 six thousand

//have a great day//

4 0
3 years ago
Read 2 more answers
What is the modulus of |9+40i|?
Talja [164]

Answer:

41

Step-by-step explanation:

We know that complex numbers are a combination of real and imaginary numbers

Real part is x and imaginary part y is multiplied by i, square root of -1

Modulus of x+iy = \sqrt{x^2+y^2}

Here instead of x and y are given 9 and 40

i.e. 9+40i

Hence to find modulus we square the coefficients add them and then find square root

|9+49i| =\sqrt{9^2+40^2} =\sqrt{1681}

By long division method we find that

|9+40i| =41


6 0
3 years ago
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Which data set could be represented by the box plot shown below?
Lapatulllka [165]

Answer:

The answer is C

Step-by-step explanation:

It starts at 25 and then it stops at 38.

I hope this helps!

6 0
2 years ago
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ASAP HELP ME GIVING BRAINLIEST
Natasha2012 [34]

Answer:B

Step-by-step explanation:

The quadratic formula can be used to solve an equation only if the highest degree in the equation is 2

7 0
3 years ago
A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

6 0
3 years ago
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