Answer: 2 kg
Step-by-step explanation:
3/4(22-x)=17-x
66/4-3/4x=34/2-x
33/2-3/4x=34/2-x
1/4x=1/2
x=2
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
1 = 3
2 = 6
3 = 9
Step-by-step explanation:
for every # it is multiplied by 3 (ex. 7 • 3 = 21, 8 • 3 = 24, ect.)
therefore if it is multiplied by 3 each time
then 1 • 3 = 3
2 • 3 = 6
and 3 • 3 = 9
hope this helps :)
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