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Daniel [21]
3 years ago
9

What is the distance between P(-3,-25) and Q(50,-2)

Mathematics
1 answer:
Karolina [17]3 years ago
4 0
Dist =   (x2-x1)^{2} +  (y2-y1)^{2}

above  is the distance formula, plugging your numbers from P(x1,y1) and Q(x2,y2).

Dist =  \sqrt{(50-(-3))^{2}  + (-2-(-25))^{2} }
or\sqrt{ 53^{2} + 23 ^{2} }


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X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
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\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
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9× 3 1/2=<br> Which choice is the most reasonable answer?
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Step-by-step explanation:

to do this, first you need to transform the <u>mixed number</u> <em>(3 1/2)</em> into an <u>improper fraction</u>, to get 7/2.

then you just multiply 9 by 7/2

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