If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Answer:
(2l + 2w) + (a + b + c)
Step-by-step explanation:
The formula for the perimeter of a rectangle is
P = 2l + 2w
so if you substitute, it becomes
P = 2(12) + 2(2)
= 24 + 4
= 28
For the perimeter of a triangle the correct formula would be
P = a + b + c
The missing side in the triangle is 3 because 15 - 12 is 3.
If you substitute, it becomes
P = 2 + 3 + 6
P = 11
If we add both perimeters together we get the full perimeter of the figure which is
28 + 11 = 39
I am not sure if you wanted the answer as well but just in case :)
Answer:
D, D, G, G,
Step-by-step explanation:
1st. Decay: This is decay because number being multiplied is less than 1.
2nd. Decay:This is decay because number being multiplied is less than 1.
3rd. Growth: This is growth because the number being multiplied is greater than 1.
4th.Growth:This is growth because the number being multiplied is greater than 1.
Answer:
Its the third answer
Step-by-step explanation:
