In standard form, zero is always on the right:
y = 12 - x^4
y + x^4 - 12 = 0

End behavior:
As x approaches ∞, y approaches -∞
As x approaches -∞, t approaches -∞

4 0

3 years ago

Graph the inequality x<1

S_A_V [24]

,,,,,,,,,,,,,m............

7 0

4 years ago

Which equation represents the polynomial function with zeros −1, 1, and 3 (multiplicity of 2), and a y-intercept of −18? (4 poin

Vlad [161]

Correct Answer:
3rd option is the correct answer

Solution:
The zeros of the polynomial are -1,1 and 3. The multiplicity of 3 is 2. So the polynomial can be expressed as:

$y=a (x-3)^{2}(x-1)(x+1)$

The y-intercept of the polynomial is -18. This means the polynomial passes through the point (0,-18). Therefore, y must be -18 when x = 0. Using these values of x and y in previous equation we get:

$-18=a (0-3)^{2}(0-1)(0+1) \\ \\ 
-18=-9a \\ \\ 
a=2$

The final equation of the polynomial becomes:

$y=2 (x-3)^{2}(x-1)(x+1)$

7 0

3 years ago