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3 years ago

15

9

x} ) ^5 " align="absmiddle" class="latex-formula"> How do you rewrite the following radical expression in rational exponent form?

2 answers:

BlackZzzverrR [31]3 years ago

8 0

<span>How do you rewrite the following radical expression in rational exponent form?
</span>9 1/2 is the answer

Maksim231197 [3]3 years ago

3 0

9 1/2 lol you're welcome I can see you and I hate him

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Dave bought 1.2 pounds of plums for $0.50 per pound he also bought 1.5 pounds of nuts for $2.50 per pound Dave gave the cashier

andre [41]

Answer:

$5.65

Step-by-step explanation:

1.20x0.50=0.60
1.50x2.50=3.75
0.60+3.75=4.35
10.00-4.35
5.65

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3 years ago

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3 years ago

Solve for x squared - 12x+59=0

dalvyx [7]

We solve the equation $x^2 - 12x + 59 = 0$

First we use $x^2 - 12x + \displaystyle\sum_{n=1}^{\sum_{i=5}^6i}\left(\frac{59}{11}\right)$ in order to compute our answer and then we use Justin Bieber's <span><em>I close my eyes and I can see a better day</em> </span> Theorem that says that

$The\ solutions\ to\ x^2 - 12x + \displaystyle\sum_{n=1}^{\sum_{i=5}^6(i)}= 0 \\ \\ \\ \ are\ x=6+\sqrt{23}i,\:x=6-\sqrt{23}i$

Here is a proof of Justin Bieber's <span>I close my eyes and I can see a better day T</span>heorem which uses the advanced techniques of mathematicians:

$x^2 - 12x + \displaystyle\sum_{n=1}^{\sum_{i=5}^6(i)}= 0 \\ 
x^2 - 12x + 59 = 0\\ 
\implies x = \frac{-(-12) \pm \sqrt{(-12)^2 - 4(1)(59)} }{2(1)} \\ 
x = \frac{12 \pm \sqrt{144 - 236} }{2} \\
x = \frac{12 \pm \sqrt{-92} }{2} \\
x = \frac{12 \pm 2\sqrt{-23} }{2} \\
x = 6 \pm 2 \sqrt{23} i \\$

6 0

4 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%3D2%28x%29%5E%7B2%7D%2B5%5Csqrt%28%7Bx%7D%20%2B2%29" id="TexFormula1" title="f(x)=2(x

Delvig [45]

Answer:

f(2)=18

Step-by-step explanation:

$f(x)=2(x)^2+5 \sqrt{x+2}\\f(2)=2(2)^2+5 \sqrt{2+2}\\=2*4+5\sqrt{4} \\=8+5*2\\=8+10\\=18$

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3 years ago

I need the answer for the target one

maksim [4K]

I don't really understand this question do u have a pic

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3 years ago