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3 years ago

15

9

x} ) ^5 " align="absmiddle" class="latex-formula"> How do you rewrite the following radical expression in rational exponent form?

2 answers:

BlackZzzverrR [31]3 years ago

8 0

<span>How do you rewrite the following radical expression in rational exponent form?
</span>9 1/2 is the answer

Maksim231197 [3]3 years ago

3 0

9 1/2 lol you're welcome I can see you and I hate him

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Determine the type and number of solutions of −4x2 − 3x + 7 = 0.

Kaylis [27]

Answer:

Step-by-step explanation:

You have to use the discriminant for this. If the quadratic is $-4x^2-3x+7$ , then

a = -4, b = -3, and c = 7. The formula for finding the discriminant is

$D=b^2-4ac$ which comes from the quadratic formula, but without the square root sign. Filling in:

$D=(-3)^2-4(-4)(7)$ which simplifies down to

D = 9 + 112 so

D = 121. This is a perfect square, so the solutions will be 2 real. Just so you know, you will NEVER have a solution like the one offered in the third choice down. If you have one imaginary root, you will ALWAYS have a second by the conjugate rule.

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3 years ago

Consider in the figure below.

yawa3891 [41]

Here BD is perpendicular bisector

So

UB=BV=74

$\\ \tt\hookrightarrow UV=74+74=148$

Apply Pythagorean theorem

$\\ \tt\hookrightarrow BD^2=UD^2-UB^2=UD^2-VD^2$

UD=VD=78=TD

$\\ \tt\hookrightarrow TC^2=TD^2-CD^2$

$\\ \tt\hookrightarrow TC^2=78^2-30^2$

$\\ \tt\hookrightarrow TC^2=6084-900=5184$

$\\ \tt\hookrightarrow TC=72$

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