Whenever you face the problem that deals with maxima or minima you should keep in mind that minima/maxima of a function is always a point where it's derivative is equal to zero.
To solve your problem we first need to find an equation of net benefits. Net benefits are expressed as a difference between total benefits and total cost. We can denote this function with B(y).
B(y)=b-c
B(y)=100y-18y²
Now that we have a net benefits function we need find it's derivate with respect to y.

Now we must find at which point this function is equal to zero.
0=100-36y
36y=100
y=2.8
Now that we know at which point our function reaches maxima we just plug that number back into our equation for net benefits and we get our answer.
B(2.8)=100(2.8)-18(2.8)²=138.88≈139.
One thing that always helps is to have your function graphed. It will give you a good insight into how your function behaves and allow you to identify minima/maxima points.
You need to a table of the standard normal cumulative distribution
Here is one:
https://math.ucalgary.ca/files/math/normal_cdf.pdf
the closest value I see is 0.85
Answer:
6 dog toys.
Step-by-step explanation:
If 2/3 of the total dog toys are squeaky, 4 is two thirds of 6, meaning Lisa has 6 dog toys.
Given:
pool length : 10 yards
pool width : 8 yards
Area = 10 yds * 8 yds = 80 yd²
(10 + 2x)(8 + 2x) = 120
10(8 + 2x) + 2x(8+2x) = 120
80 + 20x + 16x + 4x² = 120
4x² + 36x + 80 - 120 = 0
4x² + 36x - 40 = 0
4(x² + 9x - 10) = 0
4(x + 10)(x - 1) = 0
x + 10 = 0
x = -10
x - 1 = 0
x = 1
the width of the deck is 1 yard
Answer: H
Step-by-step explanation: