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denis23 [38]
3 years ago
15

Solve x2 + 4x = 4 for x by completing the square.

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

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The ratio of landline phones to cell phones at an apartment complex is 2 to 3. If there are 68 landline​ phones, how many phones
icang [17]

Answer:

170.

Step-by-step explanation:

The number of cell phones =  68 * 3/2

= 102.

Total = 102 + 68

= 170 phones.

8 0
3 years ago
HELP PLEASE!! THIS IS DUE IN AN HOUR!!
Neko [114]

Answer:

Your answer is 30.

Step-by-step explanation:

You plug in b=12, and 5=h

12*5/2

60/2

--->30<---

7 0
3 years ago
An order of 12 balls is being packed for shipment to New Jersey. Each ball is 9 inches in diameter and weighs 14 ounces. If the
DiKsa [7]
Assuming that the balls are perfect sphere, then we can use the formula for the volume of the sphere to solve the volume of the ball. the volume of a spher is given by the formula:
V = (4/3) pi r^3
where pi = 3.1416
r is the radius

since D = 9 in
r = 4.5 in

V = ( 4/3 ) (3.1416) ( 4.5)^3
V = 381.7 cubic inches is the volume of one of the balls.
3 0
3 years ago
I need help with this. I don’t understand it. Please help.
Y_Kistochka [10]

Step-by-step explanation:

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7 0
3 years ago
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The angle of elevation of the top of a radio mast from a point due east of it and 96 m away from its base is 30°. From another p
marshall27 [118]

Answer:

32 m

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Calculate the height of the radio mast using the tan trig ratio.

Given:

  • \theta = 30°
  • O = h (height of radio mast)
  • A = 96 m

\implies \sf tan(30^{\circ})=\dfrac{ \sf h}{96}

\implies \sf h=96 \tan (30^{\circ})

\implies \sf h=\dfrac{96 \sqrt{3}}{3}

\implies \sf h=32 \sqrt{3}\:\:m

To calculate the distance from the second point to the base of the mast, use the tan trig ratio:

Given:

  • \theta = 60°
  • O = 32√3 m
  • A = d

\implies \sf tan(60^{\circ})=\dfrac{ \sf 32 \sqrt{3}}{d}

\implies \sf \sqrt{3}=\dfrac{ \sf 32 \sqrt{3}}{d}

\implies \sf d=\dfrac{ \sf 32 \sqrt{3}}{\sqrt{3}}

\implies \sf d=32\:\: m

4 0
2 years ago
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