Answer:
<h3>
5</h3>
Step-by-step explanation:
z - any integer
2z+1 - any odd integer (the smaller one)
2z+1+2 = 2z+3 - odd integer consecutive to 2z+1 (the larger one)
2(2z+1) - twice the smaller number
2(2z+1) - 1 - one less than twice the smaller number
2(2z+1) - 1 = 2z + 3
4z + 2 - 1 = 2z + 3
2z = 2
z = 1
2z+3 = 2•1+3 = 5
check:
2z+1 = 2•1+1 = 3,
2(2z+1)-1 = 2(2•1+1)-1 = 2•3-1 = 5 = 2z+3
I think it could be b cause it does have sum solution or it could be A at the same time so try to used the calculator and if it comes up with less then then it could be A if it comes up with more then, then it could be B
2/8+4/8=6/8 = 2/3 I believe if there isn't some hidden text I don't understand...
Complete the recursive formula of the arithmetic sequence -15, -11, -7, -3,...−15,−11,−7,−3,...minus, 15, comma, minus, 11, comm
o-na [289]
Answer:
c(1) = -15
c(n) = c(n - 1) + 4
Step-by-step explanation:
Given arithmetic sequence is,
-15, -11, -7, -3...........
Common difference between each successive and previous term is,
d = -11 - (-15)
= -11 + 15
= 4
Since recursive formula of the arithmetic sequence is represented by,
a₁ = First term of the sequence
a(n) = a(n - 1) + d
where a(n) is the nth term and a(n-1) is the previous term of the nth term.
Form the given sequence,
c₁ = -15
c(n) = c(n - 1) + 4
Answer:
55
Step-by-step explanation:
55 is your answer
