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Artemon [7]
3 years ago
12

One weekend, a newsstand sold twice as many Sunday papers as Friday papers. The Sunday paper costs $1.50, the Friday paper costs

$0.75. How many Friday and Sunday papers were sold if the newsstand took in $116.25?
Mathematics
1 answer:
babunello [35]3 years ago
6 0

there were 51 Sunday papers sold and 53 Friday papers sold
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The answer is B I believe
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Answer:

150:120

Step-by-step explanation:

U add the 2 ratios 5+4=9

270/9=30

30*5=150

30*4=120

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
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Phantasy [73]

The odds of jimmy winning a free lunch is 0.066.

<h3>What is Probability ?</h3>

Probability is the likeliness of an event to happen.

It is given that

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jimmy puts 10 cards in the bowl.

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The odds of jimmy winning a free lunch is given by

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Therefore the odds of jimmy winning a free lunch is 0.066.

To know more about Probability

brainly.com/question/11234923

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