Ask question

Ask question

All categories

4 years ago

12

One weekend, a newsstand sold twice as many Sunday papers as Friday papers. The Sunday paper costs $1.50, the Friday paper costs

$0.75. How many Friday and Sunday papers were sold if the newsstand took in $116.25?

1 answer:

babunello [35]4 years ago

6 0

there were 51 Sunday papers sold and 53 Friday papers sold

You might be interested in

Jamilla baby sat nine times. she earned $15, $20, $10, $12, $20, $16, $80, and $18 for eight babysitting jobs. how much did she

mr Goodwill [35]

In order to earn a mean of $24 she must have earned #25 the ninth time she babysat

5 0

3 years ago

Pls answer this question

dem82 [27]

Answer:

firstly covert it like 7 1/4

= 4x7+1 = 29 so 29/4

Step-by-step explanation:

and then find difference by making denominators same

7 0

4 years ago

PLEASE HELP ASAP I'LL GIVE. BRAINLIEST

AleksandrR [38]

It would be B. 28 square yards

6 0

3 years ago

Read 2 more answers

HELP ASAP LOOK AT THE PICTURE ATTACHED!!!

malfutka [58]

Answer: infinitely many solutions

Step 1)

√25y² +16 =5y + 4

(√25y² + 40y + 16)² = (5y + 4)²

25y² + 40y + 16 = (5y + 4)²

25y² + 40y + 16 = (5y)² + 2 × 5y × 4 + 4²

25y² + 40y + 16 = 5² × y² + 2 × 5y × 4 + 4²

25y² + 40y + 16 = 25y² + 2 × 5y × 4 + 16

25y² + 40y + 16 = 25y² + 40y + 16

25y² + 40y + 16 = 25y² + 40y + 16

25y² + 40y + 16 − 25y² − 40y − 16 = 0

0 = 0

6 0

3 years ago

14. A company uses many different delivery

ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that $P(A) = 0.71$

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that $P(B|A) = 0.93$

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603$

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

8 0

3 years ago