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3 years ago

Can 4 24/35 be simplified? Please answer right away! Need an answer right away!

Mathematics

1 answer:

tatyana61 [14]3 years ago

5 0

Answer:

Step-by-step explanation:

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used books cost $2.27 each. which represents the total number of books that can be purchased for $10?

siniylev [52]

Answer:

4 books

Step-by-step explanation:

The cost for one used = $2.27

The question requires you to find the number of books that could be purchased with $10

Let assume the cost for a single used book to be $ t

If you have $ x in your pocket then the number of books you can purchase with $ x will be;

number of books= $ x/ $t.............................(a)

Applying this expression to the question;

$t= $2.27

$ x= $10

number of books = $10/$2.27 = 4.405 = 4 books

4 0

3 years ago

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FREE BRAINLY AND 50 PTS!! MIGHT BE EASY

Thepotemich [5.8K]

> and = with line through it

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3 years ago

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In a factory, 53 workers receive a wage of 7,576 each per month. Find the total wages received by all the workers for one financ

Olin [163]

Step-by-step explanation:

as you know, there are 12 months per year.

also, the word "annual" means "per year" (of again 12 months).

each worker gets 7,576 per month.

that means each worker gets an annual salary of

7,576 × 12 = 90,912

the salaries/wages of all 53 workers together in a year are then

90,912 × 53 = 4,818,336

8 0

3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

6. Complete the table for the given function.

Aleks [24]

How would be so that. Where is the graph

4 0

3 years ago