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kirill115 [55]
3 years ago
14

Help with a and describe

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

1

Step-by-step explanation:

Simply plug in 0 for x:

g(0) = 5x + 1

g(0) = 5(0) + 1

g(0) = 1

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Uptown Photography charges $15 per portrait sheet, plus $19 for a session fee. Downtown Photography charges $29 for a session fe
stepan [7]

The answer is (2,49).


7 0
3 years ago
F(x) = -4x2 + 4x – 4<br> Find f(3)
ValentinkaMS [17]

F(3) occurs when x =3. So lets plug 3 into our equation.

f(3) = -4(3)^2 + 4(3)-4\\f(3) = -4(9) + 12- 4\\f(3) = -36 + 12- 4\\f(3)= -28

F(3) = -28

I hope this helps! :)

5 0
3 years ago
How much carbon dioxide will you prevent from entering the atmosphere in one year, if you replace a 100-watt light bulb with a C
Afina-wow [57]

Answer:

280000lb

Step-by-step explanation:

In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.

Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere

Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;

100 * 1.37 * 8 * 365 = 40040 lb

Using a 30 watt CFL for 8hrs/ day for a year, we have;

30 * 1.37 * 8 * 365 = 120012 lb

Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up

3 0
3 years ago
Multiple choice please help!!
AveGali [126]

3 and 4

Step-by-step explanation:

y=5x

y=5(0)

y=0

y=5x

y=5(10)

y=50

y=5x

y=5(51)

y=255

y=5x

y=5(400)

y=2000

5 0
3 years ago
In 2013 number of students in a small school is 284.it is estimated that student population will increase by 4 percent
BaLLatris [955]

The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.

Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get

{P}_{n} =284\cdot {1.04}^{n}P

n

=284⋅1.04

n

We can find the number of years since 2013 by subtracting.

\displaystyle 2020 - 2013=72020−2013=7

We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.

\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P

7

=284⋅1.04

7

≈374

The student population will be about 374 in 2020.

5 0
3 years ago
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