8 square units
Divide figure into one square, and two triangles
Area of square:
2 x 2 = 4 square units
Area of ONE triangle:
1/2 x 2 x 2 = 2 square units
The triangles we have are both sizes, so multiply this by 2:
2 square units x 2 = 4 square units
ADD THE AREA OF SQUARE AND TRIANGLES:
4 square units + 4 square units = 8 square units
Have a nice day
Hello,
if the question is to solve the equation:
1) log must exist:
a)==>2r²-27>0==>(r-√(27/2))(r+√(27/2))==> outside the roots
r<-√(27/2) or r>√(27/2)
b)==>3r²+12r>0 ==>3r(r+4)>0 ==>outside the roots
r>0 or r<-4
==>r<-4 or r>√(27/2)=3.6742...
If this is realized:
2r-27=3r²+12r
==>r²+12r+27=0
Δ=12²-4*27=36=6²
r=(-12+6)/2=-3 or r=(-12-6)/2=-9
One solution r=-9
Proof
30 because it is in the tenths place
Answer: i got 394
Step-by-step explanation:
Answer:
The answer to this question is A. 8(3/5*1/4).