Answer:
5
ALL SIDES MUST BE THE SAME
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
Barry's kart is faster as he goes 21 Mph while Alan only goes 19.89 Mph.
Step-by-step explanation:
First to get this answer we need to convert feet per minute to miles per hour. So we multiple 1750 feet per minute by 60 to get a hour. This gets up 105000 total feet in a hour. Now we need to divide this by 5280, which is how long a mile is, to get 19.89 miles which is how many miles he travels in a hour making him travel 19.89 mph which is less than 21 making Barry faster.
Answer:
It will take 5 hours until it reaches its maximum concentration.
Step-by-step explanation:
The maximum concentration will happen in t hours. t is found when
In this problem
Applying the quotient derivative formula
A fraction is equal to zero when the numerator is 0. So
We use only positive value.
It will take 5 hours until it reaches its maximum concentration.
