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Lilit [14]
2 years ago
12

A book sold 33,200 copies in its first month. Suppose this represents 7.4% of the number of copies sold to date. How many copies

have been sold to date?
Mathematics
2 answers:
coldgirl [10]2 years ago
7 0

Answer:

448,648

Step-by-step explanation:

33,200/.074 = 448,648

Marta_Voda [28]2 years ago
6 0

Answer: 448648

Step-by-step explanation:

33,200 copies represent 7.4% of the total amount

-----------------------------------------------------

#1  33,200 ÷ 7.4%

- this is because how we get 33,200 by calculation is use the total amount and times 7.4% to get 33,200. So we are just working backwards. Since it was times before, then we divide after.

 33,200÷7.4%

=33,200÷0.074

≈448648 (you can't round up when the real amount is less the exact amount)

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Read 2 more answers
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

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9514 1404 393

Answer:

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Step-by-step explanation:

Undo what is done to p.

Multiply by 2.

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Subtract 10.

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