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mote1985 [20]
3 years ago
10

What is the answer to 54x^2-144x

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0

Step-by-step explanation:

54x^2-144x

18x(3x-8) is your answer

sergij07 [2.7K]3 years ago
4 0
The answer is 18x (3x-8)
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How do I get the answer to this step by step? pls this is a emergency
solong [7]

Answer:

X = 12

Step-by-step explanation:

If the angle depicted on top is the angle for the inside angle in the triangle, we can find x easily. a line is 180 degrees so we can do 180-151 for the right inside angle. that's 29. we can do 5x+3+9x-20+29 = 180. 14x+12=180. 14x = 180-12. 14x = 168. 168/14 = 12

5 0
2 years ago
AARP reported on a study conducted to learn how long it takes individuals to prepare their federal income tax return (AARP Bulle
Crank

Answer:

Confidence interval: (30.1,36.9)

Step-by-step explanation:

We are given the following data set:

35.3,30.5,37.4,26.5,13.0,49.9,28.8,44.0,61.6,0.5,40.5,34.9,47.9,36.6,24.1,39.8,47.8,18.5,36.6,39.2,14.5,37.3,40.5,49.3,45.5,28.3,19.5,5.6,52.6,41.4,45.3,39.0,33.7,29.4,14.5,40.1,33.7,36.9,5.6,33.7

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1339.9}{40} = 33.5

S.D = 11(given)

n = 40

Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

33.5 \pm 1.96(\frac{11}{\sqrt{40}} ) = 6.34 \pm 3.4 = (30.1,36.9)

6 0
3 years ago
What is the value of x in this equation? 5x − 2(2x − 1) = 6
MakcuM [25]

Answer:

x=4

Step-by-step explanation:

5x-4x+2=6

x+2=6

x=6-2

x=4

7 0
3 years ago
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Prove that the gregorian calendar repeats itself every 400 years.
Setler79 [48]

The calendar obviously has an integral number of years and months in 400 years. If it has an integral number of weeks, then it will repeat itself after that time. The rules of the calendar eliminate a leap year in 3 out of the four century years, so there are 97 leap years in 400 years. The number of excess days of the week in 400 years can be found by ...

(303·365) mod 7 + (97·366) mod 7 = (2·1 + 6·2) mod 7 = 14 mod 7 = 0

Thus, there are also an integral number of weeks in 400 years.

The first day of the week is the same at the start of every 400-year interval, so the calendar repeats every 400 years.

3 0
4 years ago
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