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Step2247 [10]
3 years ago
10

Which ordered pair is a solution to the system of equations? Use any method to solve. 2x-y=5 3x+2y=4

Mathematics
2 answers:
Ymorist [56]3 years ago
7 0
Elimination 

2 ( 2x -y=5)  multiply    =   4x -2y=10 
                                           3x +2y=4 
 

* add the X's and the 10 and 4         7x=14    * divide by 7  giving you    
 
                                            x=2

*and then plug back in

3(2) +2y =4
    6 + 2y = 4
           2y= -2
                y= -1

the order pair is ( 2 , -1)


kirill115 [55]3 years ago
5 0

Hi


2x-y=5

3x+2y=4

We need to solve 2x-y=5 for y

Now let's start by adding -2x to both sides

2x-y-2x=5-2x

-y=-2x+5

Divide both sides by -1 so we eliminate the negative sign

-y/-1=-2x+5/-1

y=2x-5

Now substitute 2x-5 for y in 3x+2y=4

3x+2y=4

3x+2(2x-5)=4

3x+4x-10=4

7x-10=4

Add 10 to both sides

7x-10+10=4+10

7x=14

Divide both sides by 7 so we can find the value for x

7x/7=14/7

x=2

Now substitute 2 for x in y=2x-5 so we can find the value for y

y=2x-5

y=(2)(2)-5

y=4-5

y=-1

Answer: (2,-1)


I hope that's help:0


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Which products result in a difference of squares? Select three options. A. (x minus y)(y minus x) B. (6 minus y)(6 minus y) C. (
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Step-by-step explanation:

Hello, please consider the following.

A. (x minus y)(y minus x)

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E. (64 y squared + x squared)(negative x squared + 64 y squared)

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Hope this helps.

Do not hesitate if you need further explanation.

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