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3 years ago

7

The length of a rectangle is 3cm more than twice the width. The perimeter is 84 cm. Find the dimensions .

1 answer:

blsea [12.9K]3 years ago

4 0

Width of the rectangle is 13 cm and length is 29 cm.

<u>Step-by-step explanation:</u>

Step 1:

Given perimeter of the rectangle = 84 cm. Let the width be x, then the length of the rectangle = 2x + 3. Use the formula for perimeter of a rectangle = 2(length + width) to find the dimensions.

84 = 2(2x + 3 + x) = 2(3x + 3) = 6(x + 1) [taking 3 as common factor outside)

⇒ 84 = 6x + 6

⇒ 78 = 6x

∴ x = 13

⇒ Width of the rectangle = 13 cm

∴ Length of the rectangle = 2x + 3 = 29 cm

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Answer:

Step-by-step explanation:

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3 years ago

P, Q, V, and K are collinear with V between K and P, and Q between V and K. If VP = 14x + 4, PK = x + 630, VQ = 17x + 6, and KQ

Ierofanga [76]

It's given in the question,

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VP = 14x + 4

PK = x + 630

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KQ = 11x + 5

By segment addition postulate,

KQ + VQ + VP = KP

Substitute the values in the expression,

(11x + 5) + (17x + 6) + (14x + 4) = x + 630

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x = $\frac{615}{41}$

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Therefore, value of VP = (14x + 4)

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3 years ago

The area of the city of Vancouver is 115 km^2. if the shape of Vancouver is approximately a square, how wide is the city of Vanc

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Answer:

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To solve this we first have to know the formula to calculate the area of a square

a = area = 115 km²

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now we replace with the known values

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s = 10.724km = 10.7km

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Setler [38]

Answer:

$\huge\boxed{V=64cm^3}$

Step-by-step explanation:

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