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emmainna [20.7K]
4 years ago
5

PLEASE HELP ME ASAP

Mathematics
1 answer:
goblinko [34]4 years ago
3 0

Answer:

20.04 units

Step-by-step explanation:

The diagram shows right triangle ABC. Use the definition of the cosine:

\cos \angle C=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}\\ \\\cos \angle C=\dfrac{BC}{AC}\\ \\\cos 51^{\circ}=\dfrac{BC}{27}\\ \\BC=27\cdot \cos 51^{\circ}\\ \\BC\approx 20.04\ units

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Use long division to find the value of 1,875÷5.
Naddik [55]

Answer:

375

Step-by-step explanation:

I have a specific way to find this but I can't exactly explainit, I only know how to show, so sorry if that is useless, I am not very helpful

3 0
3 years ago
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I need help with #10!
DiKsa [7]

Answer: 6 years old.

Step-by-step explanation:

For this exercise let "x" represents your present age.

According to the information provided in the exercise, you know that  In three years, Chad will be three times your present age.

Then, your age in three years can be represented with the following expression:

x+3

Knowing at that time Chad's age will be three times yours and you will be half as old as old as Chad, you can write the following equation to represent this situation:

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You get that this is:

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7 0
3 years ago
Help me in this question
KATRIN_1 [288]
H = -5t^2 +5t + 10

a) t = 0, h = 10 at time 0 

b) h = (-5t  + 10) ( t  +  1) 

c) put 0 in for the height and set each factor = to 0 and solve each
0 = (-5t + 10) and 0 = (t + 1)
solve each t = 2 and t = -1, so t = 2 sec is your solution

d)  because a parabola is symmetric, the max will be half way between -1 and 2, at t = 1/2

h = -5(1/2)^2 +5(1/2) + 10
h = -5(1/4) + 5/2 +10
h = -5/4 + 5/2 + 10
h = -5/4 + 10/4 + 40/4
h = 45/4

5 0
3 years ago
Need help someone please do
Bas_tet [7]

two other ratios are 3:4 and 3/4

4 0
3 years ago
Rearrange then factorise x^2-5x+19=5x+3
Tema [17]

Answer:

x = ±4i or x = ±√-16

Step-by-step explanation:

x² - 5x + 19 = 5x + 3

x² + 16 = 0

x² = -16

x = ±√-16  (a negative square root is an imaginary number)

4 0
3 years ago
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