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MatroZZZ [7]
3 years ago
10

V3

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

Question:

The angle \theta_1 is located in Quadrant III, and sin(\theta_1) = - \sqrt{\frac{3}{2}}.

What is the value of cos(\theta_1) ?

Express your answer exactly. cos(\theta1) = ________

Answer:

cos(\theta_1) = - \frac{1}{2}

Step-by-step explanation:

Given:

sin(\theta_1) = - \sqrt{\frac{3}{2}}

Since the angle \theta_1 is located in Quadrant III, we have:

sin(\theta_1) = sin(\pi + \frac{\pi}{3})

\theta_1 = \pi + \frac{\pi}{3}

\theta_1 = \frac{4 \pi}{3}

Thus, cos(\theta_1) =

cos(\theta_1) = cos(\pi + \frac{\pi}{3})

cos(\theta_1) = -cos(\frac{\pi}{3})

cos(\theta_1) = - \frac{1}{2}

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<h3>Answers:</h3>

14.  Each leg is   21\sqrt{2}  units long.

15 (a). The longer leg is 7\sqrt{3}  units long

15 (b). The hypotenuse is 14 units long

=====================================================

Explanations:

For a 45 degree right triangle, aka 45-45-90 triangle, the hypotenuse is equal to sqrt(2) times the short leg. Algebraically we can say

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y = x\sqrt{2}\\\\x\sqrt{2} = y\\\\x = \frac{y}{\sqrt{2}}\\\\x = \frac{y\sqrt{2}}{\sqrt{2}*\sqrt{2}} \ \text{rationalizing denominator}\\\\x = \frac{y\sqrt{2}}{2}\\\\

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---------------------------

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