Compound O (C6H8) reacts with two molar equivalents of hydrogen in the presence of a catalyst to produce P (C6H12). The proton-d

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Compound O (C6H8) reacts with two molar equivalents of hydrogen in the presence of a catalyst to produce P (C6H12). The proton-d

ecoupled 13C spectrum of O consists of two singlets, one at δ 26.0 and one at δ 124.5. In the DEPT 13C spectrum of O the signal at δ 26.0 appears as a CH2 group and the one at δ 124.5 appears as a CH group. Note: All structures should be drawn with no bonds between carbon and hydrogen. Draw the correct structure for O and P

Chemistry

1 answer:

mixer [17] · Answer 1 · 2022-04-06T13:49:50+03:00

Answer:

Cyclohexadiene is converted to cyclohexane

Explanation:

Let's go in order of statements mentioned in question.

As we see from the formula it is a hydrocarbon. If it reacts with two equivalents of hydrogen, then it is either an alkyne or diene. Due to number of protons and only two signals in C13 NMR it must be a cyclic diene with only two types of Carbon atoms wich is a cyclohexadiene (it supposes to have only two signals in NMR). The generated spectra on the second picture proves that. And after hydration it becomes ordinary cyclohexane.