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4 years ago

Which bond is broken when energy is released?

2 answers:

7 0

Energy can be released or absorbed when various chemical bonds form or are broken. Exothermic reactions release energy in the form of heat whereas endothermic reactions absorb energy.

blsea [12.9K]4 years ago

4 0

Energy is released when a new bonds form.

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I need help here. Did I make any mistakes in any of the equations. Can you please check my work? Please only answer if you know

quester [9]

Answer:

yes it is all corect

Explanation:

4 0

3 years ago

Read 2 more answers

the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to

Katarina [22]

Answer: The new pressure will be 101.46 kPa.

Explanation:

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are initial pressure and temperature.

$P_2\text{ and }T_2$ are final pressure and temperature.

We are given:

By using conversion factor: $T(K)=T(^oC)+273$

$P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K$

Putting values in above equation, we get:

$\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa$

Hence, the new pressure will be 101.46 kPa.

3 0

3 years ago

12 = 3X X = 7X = 57 X = 11X = 27.7 X =

dybincka [34]

Answer:
1. $x=4$
2. $x=\frac{57}{7}$
3. $x=\frac{27.7}{11}$

Explanation:

Given the following questions:

$12=3x$
$7x=57$
$11x=27.7$

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
$12=3x$
$\frac{3x}{3} =\div3$
$12\div3=4$
$x=4$

Question two:
$7x=57$
$\frac{7x}{7} =\div7$
$57\div7=8.14285714=\frac{57}{7}$
$x=\frac{57}{7}$

Question three:
$11x=27.7$
$\frac{11x}{11} \div11$
$27.7\div11=2.51818182=\frac{27.7}{11}$
$x=\frac{27.7}{11}$

Hope this helps.

3 0

2 years ago

A 5.20 mol sample of solid A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B and C. The concentr

ELEN [110]

Answer:

2.60 moles of A remaining.

Explanation:

According to Le Chatelier's principle, the equilibrium would shift if the volume, concentration, pressure, or temperature changes.

In this question, we were told that the volume doubles, that implies that we would have to double the molarity of B/ C (since B=C.)

However, it is obvious and clear from the given equation of the reaction that A is solid in it's activity = 1. Hence, it is then ignored.

So doubling B would be 1.30 M × 2 = 2.60 M

i.e 2.60 M moles of A was consumed.

Now; the number of moles of A remaining is 5.20 - 2.60 = 2.60 moles of A remaining.

5 0

3 years ago

GOOD REWARD I will report those who gives random answers.

Helen [10]

Answer:

3 mol AlCl₃.

Explanation:

Hello!

In this case, according to the specified reactants and products, it is possible to set up the following balanced chemical reaction:

$Al(NO_3)_3+3NaCl\rightarrow 3NaNO_3+AlCl_3$

Whereas we evidence the 1:3 mole ratio between aluminum nitrate and sodium chloride; thus, since different moles were reacting, we need to identify the limiting reactant by computing the moles of AlCl₃ produced by each reactant as follows:

$n_{AlCl_3}^{by\ Al(NO_3)_3}=4molAl(NO_3)_3*\frac{1molAlCl_3}{1molAl(NO_3)_3} =4molAlCl_3\\\\n_{AlCl_3}^{by\ NaCl}=9molNaCl*\frac{1molAlCl_3}{3molNaCl} =3molAlCl_3$

Thus, we infer that NaCl is the limiting reactant as it produces the fewest moles of AlCl₃; consequently the produced amount of this product is 3 mol.

Best regards!

5 0

3 years ago