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Sphinxa [80]
3 years ago
6

Which system of equations is represented by the graph?

Mathematics
2 answers:
slavikrds [6]3 years ago
5 0

The red line has a y-intercept of -4, so the linear equations of choices A and C can be eliminated.

The numerator of the rational expression of choice B will not be zero when x=4, so that choice can be eliminated. (That is, check to see if the point (4, 0) satisfies the equation. It does not.)

The problem requirements are met by the last choice:

d y = x minus 4, over x plus 2

y = x − 4

Mkey [24]3 years ago
5 0

Answer:

d y = x minus 4, over x plus 2

y = x − 4

Step-by-step explanation:

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A jar contains n nickels and d dimes. There are 24 coins in the jar, and the total value of the coins is $1.90. How many nickels
oee [108]

Answer:14 dimes 10 nickels

Step-by-step explanation:

24 coins total

14 X.10 = 1.40

10 x .05 = .50

1.40 + .50 = 1.90

3 0
3 years ago
Drag each label to the correct location on the table. Each label can be used more than once, but not all labels will be used.
Natalka [10]

Answer:

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Step-by-step explanation:

7 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
In a sales effectiveness seminar, a group of sales representatives tried a few approaches to selling a new automobile to a custo
Ksju [112]

Answer:

1. P(S) = 373/580

2. P(S|A) = 53/116

3. P(S|Pa) = 481/580

Step-by-step explanation:

Given

---------------------Sale ----- No Sale-----Total

Aggressive ----265 --------315 ----------580

Passive ----------481 ---------99 -----------580

Total --------------746---------414------------1160

A = aggressive approach,

Pa = passive approach,

S = sale,

N= no sale.

(a) Computing P(S)

This is calculated as the division of customers that participated in sales by total customers

Customers that participated in sales = 265 + 481 = 746

Total Customers = 1160

P(S) = 746/1160

P(S) = 373/580

b.

P(S|A) means that the probability that a sales occur given that the aggressive method was used.

To solve this, we check the cell where Sales and Aggressive intersect

The cell element = 265

Total = 580

P(S|A) = 265/580

P(S|A) = 265/580

P(S|A) = 53/116

c.

P(S|Pa) means that the probability that a sales occur given that the passive method was used.

To solve this, we check the cell where Sales and Passive intersect

The cell element = 481

Total = 580

P(S|Pa) = 481/580

8 0
3 years ago
Please help me on this question, if your smart in math.
Zanzabum
It's HL because
there are two right triangles ABD and BCD
1) hypotenuses are equal (it is given that BD=AC)
2)Triangles have common leg so it is equal for both triangles

Answer: HL
8 0
3 years ago
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