Question

Suppose there are 5x 10 to the power of bacteria in 2 L of water. How many bacteria are there in 5 L of water?

Answer 1

Answer:

$12.5 x^{10}$  number of bacteria

Step-by-step explanation:

given as :

The Number of Bacteria in 2 L of water = $5 x^{10}$

∵   2 L of water have = $5 x^{10}$ number of bacteria

So  1 L of water have = $\frac{5 x^{10}}{2}$  number of bacteria

∴    5 L of water have = $\frac{5 x^{10}}{2}$ × 5 number of bacteria

                                    = $12.5 x^{10}$  number of bacteria

Hence in 5 L of water , $12.5 x^{10}$  number of bacteria available   Answer