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netineya [11]
3 years ago
14

Suppose there are 5x 10 to the power of bacteria in 2 L of water. How many bacteria are there in 5 L of water?

Mathematics
1 answer:
vivado [14]3 years ago
4 0

Answer:

12.5 x^{10}  number of bacteria

Step-by-step explanation:

given as :

The Number of Bacteria in 2 L of water = 5 x^{10}

∵   2 L of water have = 5 x^{10} number of bacteria

So  1 L of water have = \frac{5 x^{10}}{2}  number of bacteria

∴    5 L of water have = \frac{5 x^{10}}{2} × 5 number of bacteria

                                    = 12.5 x^{10}  number of bacteria

Hence in 5 L of water , 12.5 x^{10}  number of bacteria available   Answer

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Allisa [31]

Answer: 3

Step-by-step explanation:

3:1

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6 0
3 years ago
Please help!
lana66690 [7]

Answer:

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Step-by-step explanation:

Given the recursive formula

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Which expression is equivalent to sine startfraction 7 pi over 6 endfraction?
never [62]

The equivalent expression to the given one is -sin(pi/6).

<h3></h3><h3>Which expression is equivalent to the given one?</h3>

The given expression is:

sin(7pi/6)

Where the argument is in radians.

Remember that:

sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

Now we can rewrite:

sin(7pi/6) = sin(pi + pi/6)

Then we can use the above relation to rewrite:

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And we know that:

sin(pi) = 0

cos(pi) = -1

Then we can write:

sin(7pi/6) = - sin(pi/6)

If you want to learn more about the sine function:

brainly.com/question/9565966

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3 0
2 years ago
Which table of ordered pairs represents a proportional relationship?​
Alexandra [31]

Answer:

B

Step-by-step explanation:

2x5=10

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8 0
3 years ago
Solve for w<br> -2w=-30<br> Simplify your answer as much as possible.<br><br> 20 POINTS
RUDIKE [14]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
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