Answer:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
Step-by-step explanation:
1) We set up our null and alternative hypothesis as
H0: proportion of fatal bicycle accidents in 2015 was the same for all days of the week
against the claim
Ha: proportion of fatal bicycle accidents in 2015 was not the same for all days of the week
2) the significance level alpha is set at 0.05
3) the test statistic under H0 is
χ²= ∑ (ni - npi)²/ npi
which has an approximate chi square distribution with ( n-1)=7-1= 6 d.f
4) The critical region is χ² ≥ χ² (0.05)6 = 12.59
5) Calculations:
χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28
χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]
χ²= 1/14.28[8.1364]
χ²= 0.569= 0.57
6) Conclusion:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week
If r = -3 and s = 5:
(r^-4)(s^2) = (-3^-4)(5^2) = (1/81)(25) = 25/81
If r = 5 and s = -3:
(r^-4)(s^2) = (5^-4)(3^2) = (1/625)(9) = 9/625
Step-by-step explanation:
DE = 5x-2
DF = 3(x+3)
3(x+3) = 3 + 5x-2
3x+9= 5x+1
2x=8
x=4
DE=5×4-2=18
DE=18
Answer:
the probability that 3 blue chips ( or red chips) are chosen is P(X=3) = 1/14
Step-by-step explanation:
Since the X= choosing x blue chips, then P(X) follows an hypergeometric distribution , when sampling is done without replacement
P(X=x) = (C,x) * (N-C , n-x) /( N ,n)
where ( ) represents combinations then
N= population size = 8 chips
n = sample size = 3 chips
C = number of blue chips = 4 chips
x= number of blue chips that are chosen = 3 blue chips
replacing values
P(X=3) = (4,3) * (8-4 , 3-3) /( 8 ,3) = (4,3) * (4 , 0 ) /( 8 ,3) = 4 * 1 / [ 8!/(3!*5!) ] =
4*3!*5! /8! = 1/14
P(X=3) = 1/14
Answer:
Kela will be able to travel for 7 stops before her money runs out.
Step-by-step explanation:
Since Kela wants to visit a friend who lives 8 kilometers away, and she'll ride the subway as she can before walking the rest of the way, and she needs to buy an access pass that costs $ 5.50 and there is also a fee of $ 1.25 for each stop, if Kela doesn't want to spend more than $ 15 on the trip, to determine the largest number of stops she can afford, the following calculation must be performed:
(15 - 5.5) / 1.25 = X
9.5 / 1.25 = X
7.6 = X
Therefore, Kela will be able to travel for 7 stops before her money runs out.
