The width of the square is 7 cm. This is also the diameter of the circle.
To find the area of the square, you do 7², which is 49 cm².
To find the area of a circle, you do πr².
The radius is half the diameter, so it's 7 ÷ 2, which is 3.5 cm.
π3.5² ≈ 38.4845100065 cm².
The shaded region is the area of the square minus the area of the circle.
49 - 38.4845100065 = <span>10.5154899935, but because you're using 3.14 to approximate pi, the closest answer is 10.54 cm</span>².
The answer is 10.54 cm².
The correct answer is: [A]: " Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1 . That value is the unit rate."
<h3>What is y-value?</h3>
The vertical value in a pair of coordinates. How far up or down the point is. The Y Coordinate is always written second in an ordered pair of coordinates (x,y) such as (12,5). Also called "Ordinate".
Here, The "y-axis" is located on the "vertical axis" that represents the "dependent variable" (or, at times, the "control value") that cannot be "manipulated" / controlled/ or "selected" / since it represents the "y-value" of the corresponding coordinate to which the "x-value" happens to corresponds to at the given value for "x" .
Thus, the correct answer is: [A]: " Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1 . That value is the unit rate."
Learn more about Y-value from:
brainly.com/question/3319387
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Answer:
successful odds are a and c
The area of the sector which is the white triangle adding the shaded region is 68.9/360*π*9.28^2=51.78005(rounding to 5th digit after decimal point for accuracy before we do final round for answer)
The area of the white triangle in the sector has area 1/2*9.28^2*sin(68.9)= 40.17223(rounding to 5 digits again for some accuracy.
Now we take out the white triangle from the sector.
51.78005-40.17223=11.60782
rounding to the nearest tenth we get 11.6 cm^2
Problem done!
Hope this helped and if you have any questions about my explanation just ask in the comment and I will answer.
