Answer:
4cm^2
Step-by-step explanation:
First we need to find the length of the height of the triangle using Pythagoras:
a^2+b^2=c^2 (Substitute in what we have)
a^2+3√2(^2)=2√5(^2) = a^2 + 18 = 20 -> 20-18=2 √2=BD
Now we can find the area:
AD+DC= 3√2 + √2 = 4√2 x √2 = 8/2 = 4
a) f(4) = 3*4 - 4
= 8
b) h(-3) = 5 - ( - 3)
= 5 + 3 = 8
c) h(4) - f(-5) = 1 + ( -19)
= -18
have a nice day <3
The student is not correct.
Absolute value means distance from zero
|-9| = 9
|4| = 4
Since 9 is greater than 4,
|-9| is greater than |4|
In other words, -9 is further from zero then 4
The answer is
a) 11/15
b) 1/18
TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = 112°, 112°, 68°.
