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3 years ago

I need help with my homework please answer this correctly

Mathematics

1 answer:

Alla [95]3 years ago

5 0

98,561

By following the rules for each digit, your answer should be 98,561

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I NEED HELPPP AHHHHHH!!!!!!!!!!!!!!!!!!!!!!!!

Tju [1.3M]

5. complementary = 80 degrees
supplementary = 170 degrees

6. complementary = 47.5 degrees
supplementary = 137.5 degrees

7. complementary = 10 degrees
supplementary = 100 degrees

8. false
9. true
10. true
11. true
12. false
13. true
14. false

6 0

3 years ago

Read 2 more answers

160 is_% less than 200?

zmey [24]

Answer:

20%

Step-by-step explanation:

7 0

3 years ago

Work out the angle of elevation from the

insens350 [35]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:Angle \:\: of \:\: elevation= 30°$

____________________________________

$\large \tt Solution \: :$

Let the angle of elevation be " x "

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{9 \sqrt{3} }{18}$

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{ \sqrt{3} }{2}$

$\qquad \tt \rightarrow \: x = \cos {}^{ - 1} \bigg( \cfrac{ \sqrt{3} }{2} \bigg )$

$\qquad \tt \rightarrow \: x = 30 \degree \: \: or \: \: \cfrac{ \pi}{6} \: \: rad$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago

Read 2 more answers

You work on the 60th floor of 100 story building. You walk into your office and find a bomb sitting on your desk. It reads 90 se

lys-0071 [83]

Depends how strong the bomb is. If the bomb is weak then you would most likely go up 20-30 floors. If the bomb is in the middle go to the stair case and prepare for impact. If the bomb is strong go down 40 floors if possible. If none of this is possible to do and you don't know what to do about it then you must do the following:

Cut all of the wires in the bomb. Get the bomb near of a wall or a window. If it is a window then throw the bomb out of the window. If it is a wall put it as close to the wall as possible gather all your coworkers and run off of the floor.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago