Question

The sum of 5 consecutive integers is 110.What is the fourth number in this sequence?​

Answer 1

Given:

The sum of 5 consecutive integers is 110.

Let the sequence be x, x + 1, x + 2, x + 3, x + 4

We need to determine the fourth number in the sequence.

Value of x:

Since, the sum of 5 consecutive integers is 110.

Thus, we have;

$x+x+1+x+2+x+3+x+4=110$

Adding the like terms, we have;

$5x+10=110$

       $5x=100$

         $x=20$

Thus, the value of x is 20.

Fourth term:

The fourth term of the sequence is x + 3

Substituting x = 20 in the term, we get;

Fourth term = 20 + 3 = 23

Thus, the fourth term of the sequence is 23.