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Nutka1998 [239]
3 years ago
9

Can someone help me please

Mathematics
2 answers:
yuradex [85]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The angle is the same  so they would both be 60 degrees.

Makovka662 [10]3 years ago
3 0

Answer:

c.  60 = (x + 45)

Step-by-step explanation:

the angles opposite each other when two lines cross. they are always equal.

in this example 60° and (x + 45)° are vertically opposite angles.

"vertical" refers to the vertex (where they cross), NOT up/down.

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Find the 37th term of 27, 19, 11​
Akimi4 [234]

Answer:

291

Step-by-step explanation:

37=11+(37-1)*8

37 is the term you want

11 is the first term from least to greatest

(37-1) is from the term you want minus 1

*8 because 8 is the difference between each term

6 0
3 years ago
Drag and Drop the correct answer into the boxes below.
scoray [572]

Answer:

the first blank is 100

the second is 80

Step-by-step explanation:

7 0
2 years ago
How many solutions doe
musickatia [10]

Answer:

Given equation have two solutions.

x = -\frac{5}{2} and -\frac{8}{3}

Right option is (D)

Step-by-step explanation:

We have given,

6x^{2} +40=-31x

we can rewrite this equation in the form given as:

6x² + 40 + 31x = 0

or 6x² + 31x + 40 = 0

On solving this quadratic equation, we get :

x = -\frac{5}{2} and -\frac{8}{3}

That means, given equation have two solutions.

Right option is (D)

8 0
3 years ago
Read 2 more answers
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
In the diagram, polygon ABCD is flipped over a line of reflection to make a polygon with vertices at A′, B′, C′, and D′. Points
DIA [1.3K]
<span>if point A( 2,2) is reflected across the line Y then the new position A' is (-2,2) and the distance AY = distance A'Y if A is reflected across line R it is now at point B and the distance AR = distance BR lets say the point A(2,2) was perpendicular to the line R at the point (1, 4) then when reflected the point A now at location B will have coordinates</span><span>when flipped over a line of reflection the lengths are still the same the point to the line of reflection is the same length as the line of reflection to the reflected position the distance from the original point to the reflected point is twice the distance from the original point to the line of reflection cannot see your polygon. here is an example

</span>

7 0
3 years ago
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