Answer:
a) what is the probability that Neither will of these products launch ?
= 0.30
b) At least one product will be launched ?
= 0.70
Step-by-step explanation:
From the above question, we have the following information:
P(A) = 0.45
P(B) = 0.60
P(A ∩ B) = P(A and B) launching = 0.35
Step 1
We find the Probability that A or B will launch
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
a) what is the probability that Neither will of these products launch ?
1 - Probability ( A or B will launch)
= 1 - 0.70
= 0.30
b)At least one product will be launched?
This is equivalent to the probability that A or B will be launched
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
Answer: second option
Step-by-step explanation: To solve this problem, we will need to plug in the value of “x” into our equation to see if it makes sense.
Let’s start by going in order.
-4.9 = -5.7 + 10.6 = 4.9
This will not be the answer because it’s positive 4.9 not negative.
Let’s go on to the last one. If we add positive 0.8 to negative 5.7 we will get the answer of -4.9 and this makes sense.
Using polynomial long division, we get
3x^3+6x^2+11x
_____________
(x+2) | 3x^4-x^2+cx-2
-(3x^4+6x^3)
____________
6x^3-x^2+cx-2
- (6x^3+12x^2)
_____________
11x^2+cx-2
-(11x^2+22x)
__________
(22+c)x-2.
If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.
For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
Answer:
When finding these problems we always have to do the opposite of the operation shown.
In this case its:
5x + 15 = 45
Subtract 15 from both sides (we start off with constants and numbers that are being shown) The reason why its subtraction is because since your adding 15 to 5x the opposite of that is subtraction so use the number shown by itself and subtract it from both sides.
5x = 30
Divide by 5 on both sides since the opposite of 5x is division (only use the number that is shown) We have to get rid of all the numbers on the left.
therefore you'll be left with:
X = 6
Answer: sorry about that Evaluate for y=8
9x+(4)(8)
9x+(4)(8)
=9x+32
Hope this help :D
