Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.
Y = 6^2 = 36
36 is not 0 so (6,0) is not a solution
To solve this problem, you have to determine the value of
the number 3 in both numbers:
6,300 – the number 3 is in the hundreds place so its value
is 300
530 – the number 3 is in the tens place so its value is 30
To answer the question, the value of 3 in 6,300 is 10 times
the value of 3 in 530.
Answer:
3.6 and 1.2
Or
-3.6 and -1.2
Step-by-step explanation:
Let x and y be the two numbers
xy = 4.32
x/y = 3
x = 3y
3y² = 4.32
y² = 1.44
y = +/- 1.2
x = +/- 3.6
Answer:
−7
Step-by-step explanation:
