Answer: 193.3125
Step-by-step explanation:
It deleted my entire explanation um-
Anyways, calculate the area of the rectangle, length x width (7 * 15) and the semicircle (i did pi times radius squared and halved it to get the semicircle)
Basically, 105 plus the semicircle is 193.
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Answer:</h2>
∠LMN is a right angle
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Step-by-step explanation:</h2>
If we want to prove that two right triangles are congruent by knowing that the corresponding hypotenuses and one leg are congruent, we begin as follows:
- Since two legs are congruent and we know this by the hash marks, then the triangle ΔLKN is isosceles.
- By definition LN ≅ NK
- If ∠LMN is a right angle, then MN is the altitude of triangle ΔLKN
- Also MN is the bisector of LK, so KM ≅ ML
- So we have two right triangles ΔLMN and ΔKM having the same lengths of corresponding sides
- In conclusion, ΔLMN ≅ ΔKMN
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
Answer:
How much is each pizza and how much is each drink? set up your equation as 4p+5d = (your answer)
Step-by-step explanation:
F(x) + g(x)
3x-7+6x+4
=9x-3
