Question

Area of a triangle with verticals of (-4,1),(-7,5),(0,1)

Answer 1

Answer:

$8 ft^2$

Step-by-step explanation:

I assume that the three points given are the vertices of the triangle. So the three points are:

A (-4,1)

B (-7,5)

C (0,1)

The area of a triangle is given by:

$A=\frac{1}{2}bh$

where b is the base and h is the height.

Here we can take as follows:

- We can take the base to be the side AC, so that its length is equal to the distance between the two points:

$AC=\sqrt{(0-(-4))^2+(1-1)^2}=4$

- The height of the triangle is therefore the perpendicular distance between AC and point B. This is equivalent the difference in the x-coordinate between any point on AC and B, so:

$h=(5-1)=4 ft$

Therefore, the area of the triangle is:

$A=\frac{1}{2}(4)(4)=8 ft^2$